Rearranging matrix in ascending order for value in a column

   0.748151592823709   0.913337361501670   0.996134716626885   0.961898080855054
   0.450541598502498   0.152378018969223   0.078175528753184   0.004634224134067
   0.083821377996933   0.825816977489547   0.442678269775446   0.774910464711502
   0.228976968716819   0.538342435260057   0.106652770180584   0.817303220653433

Let's consider I have a matrix like this. I want to rearrange the matrix based on value in the last column in ascending order, so that I would look like below

0.450541598502498 0.152378018969223 0.078175528753184 0.004634224134067

0.083821377996933 0.825816977489547 0.442678269775446 0.774910464711502

0.228976968716819 0.538342435260057 0.106652770180584 0.817303220653433

0.748151592823709 0.913337361501670 0.996134716626885 0.961898080855054

I would do it manual for this case, but my data matrix is 500*8. Is there any option?

Answer 1

[KSSV]

k = [   0.748151592823709   0.913337361501670   0.996134716626885   0.961898080855054
   0.450541598502498   0.152378018969223   0.078175528753184   0.004634224134067
   0.083821377996933   0.825816977489547   0.442678269775446   0.774910464711502
   0.228976968716819   0.538342435260057   0.106652770180584   0.817303220653433];

[val,idx] = sort(k(:,end)) ;
iwant = k(idx,:)