how can i write an m-file function that stimulates one or more dice with each die giving values from 1 to 6?

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[James Tursa]

What have you done so far? Please post your code and ask specific questions about it. Then we can offer suggestions and corrections.

[Walter Roberson]

See also someone else's http://www.mathworks.com/matlabcentral/answers/317777-can-anyone-help-me-write-a-matlab-m-file-function-dice-m-which-simulates-one-or-more-dice-with which is the same question.

[Rola Zayn]

i just don't know how to write the stipulation and what do i have to do if someone posted the same question its not my fault if we happen to study from the same slides this is supposed to be an open community not accusatory

[James Tursa]

I don't see anything posted thus far that is accusing anybody of anything. We have simply asked you to post your current code and ask specific questions about it so we can help you.

[Rola Zayn]

then why close my question? iam merely not familiar with this type of exercise so iam asking what course of action shall i take i dont want a ready solution i want someone to explain what i should do..as is the point of this whole community.

[Walter Roberson]

I closed it accidentally because I did not read the posters name closely enough and thought it was a duplicate question. I noticed a few seconds later and re-opened it.

Answer 1

[Walter Roberson]

"i just don't know how to write the stipulation"

randi(6)

[Walter Roberson]

https://www.mathworks.com/help/matlab/ref/function.html

[Rola Zayn]

Thank you.

[John BG]

do you want laden or unladen die?

[Walter Roberson]

African or European?

Answer 2

[Image Analyst]

My only dice demo is one that I wrote demonstrating the Einstein Oppenheimer dice game. It's a fascinating puzzle or paradox that I think everyone will find truly intriguing. The relevant "die rolling" line is this:

sides = randi(6, 1, 2);  % Roll two six-sided dice

Here is the description at the beginning:

% Intransitive dice - "rock paper scissors" dice.
% http://tierneylab.blogs.nytimes.com/2009/03/30/the-god-einstein-oppenheimer-dice-puzzle/
%
% God does not throw dice, Albert Einstein famously declared, but suppose he was wrong. 
% Suppose God decided to demonstrate otherwise by showing up one day at the Institute for Advanced Study. 
% God announces that dice games are in fact wildly popular in heaven, 
% and that the purpose of this visit it to teach a new game to Einstein and J. Robert Oppenheimer. God explains the rules:
% There are three blank dice. First, Oppenheimer will take each of the six-sided dice 
% and write the numbers from 1 to 18, in any order he likes, on the 18 faces of the three dice. 
% Einstein will then examine the dice and select one of them as his own. 
% Oppenheimer will then examine the remaining two dice and select one of them. 
% (The third die will be discarded.) Oppenheimer and Einstein will then play repeated rounds
% of “Dice War” in which they roll the dice simultaneously, with a point being awarded each round 
% to the player who rolls the higher number. The player with the most points wins.
% Assume that Oppenheimer and Einstein employ the smartest possible strategies, 
% and that the outcome will be determined by the laws of probability (meaning that God doesn’t skew the dice 
% or the influence the rolls). Which player, if either, is favored to win?
%
% Essentially, Oppenheimer creates a set of 3 "rock paper scissor" dice, 
% ensuring that whichever one die Einstein chooses, Oppenheimer can pick one of the 
% other two dice that will, on average, beat the die Einstein chose.
% 
% The question is then, can we create a set of ‘rock paper scissor’ dice? We can, and the set is:
% 
% 18 17 10 9 2 1 for the first die;
% 16 15 8 7 6 5 for the second;
% 14 13 12 11 4 3 for the third.
% 
% Die 1 will beat die 2 on average 5/9ths of the time, but will lose 5/9ths of the time to die 3.
% Die 2 will beat die 3 on average 5/9ths of the time, but will lose 5/9ths of the time to die 1.
% Die 3 will beat die 1 on average 5/9ths of the time, but will lose 5/9ths of the time to die 2.
% 
% Therefore, whichever die Einstein chooses, Oppenheimer can pick one such
% that he will win on average 5/9ths of the time.
% — Ioan Wigmore
%
% MATLAB code by Image Analyst

I do have some fun demos on random walks and Monte Carlo simulations (like the famous Monty Hall problem) if you're interested - just ask.