Direction Cosine Matrix using left-handed coordinate system?

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Hi, is there any reason why angle2dcm uses a left-handed coordinate system?
angle2dcm(pi/6, 0, 0, 'XYZ') =
1.0000 0 0
0 0.8660 0.5000
0 -0.5000 0.8660
When I multiply this with a vector in z-direction I can see that the function does not follow the right hand rule for rotation. The function rotx however rotates the other way round. I'm using a simulink 6dof model block. Matlab help says that the dcm which is one of the block outputs gives me the transformation from inertial to body and the used system is a right-handed system. Does anyone know why Matlab is doing this?
  2 Commenti
John D'Errico
John D'Errico il 29 Dic 2016
It is always nice if you tell people where (which toolbox) a function comes from. Don't force people to search for it, as that just makes them work to answer your question. You want to make it as easy as possible to get an answer.
Tilman
Tilman il 29 Dic 2016
Sorry, the 6dof is part of the aerospace toolbox. angle2dcm is standard Matlab I think.

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Matt J
Matt J il 29 Dic 2016
Modificato: Matt J il 29 Dic 2016
I can't be sure, but some Matlab Toolboxes (e.g., Image Processing) like to represent coordinates as row vectors instead of column vectors. This means they need to perform transformations by right-multiplying row vectors with transformation matrices instead of left-multiplying. If this is the convention of the Aerospace Toolbox as well, the result
R=angle2dcm(pi/6, 0, 0, 'XYZ')
is perfectly consistent with a right handed system. You are simply meant to be executing the transform as [0,0,1]*R instead of R*[0;0;1].
  1 Commento
Tilman
Tilman il 30 Dic 2016
Modificato: Tilman il 31 Dic 2016
Thank you very much. angle2dcm is actually from the aerospace toolbox, too. It also looks like Simulink uses row vectors by default.

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