matrix corresponing to the minimum value of the difference

m=2
t=[1 0 0; 0 (1/sqrt(2)) (1/sqrt(2))];
v1=0.956
v2=2.4
a=[ 0 1 0];
    b=[0 1 1];
    p=b-a;
    d1=m*a;
    for x=1:1:m+1
    c=d1+p*(x-1)
    f=transpose(c);
    vndq=t*c;
    vnq=vndq(1,1)
    vnd=vndq(2,1)
    d(x)=abs(v2-vnq)+abs(v1-vnd)
    n=min(d)
    end

In the given code minimum value of d matrix corresponding c matrix

[Adam]

Please format your code correctly in a {} Code block and don't use all capitals.

[JAGADEESH JAGA]

Thanks for the suggestion. it does not detail whether about capitals as all are variables and I used for it for highlighting. if u wish change the code.

[Stephen23]

@JAGADEESH JAGA: it is not the capitals in the code, but the capitals in the English that is the problem: on most forums this is considered to be "shouting", and is not very polite (do an internet search):

http://netiquette.wikia.com/wiki/Rule_number_2_-_Do_not_use_all_caps

https://newrepublic.com/article/117390/netiquette-capitalization-how-caps-became-code-yelling

Communicating on an online forum is just like real life: the more polite and considerate you are, the more help you will receive.

[Walter Roberson]

Duplicated by http://www.mathworks.com/matlabcentral/answers/323166-c-row-matrix-corresponding-to-the-minimum-value-of-the-distance-of-the-matrix

Answer 1

[Niels]

DEAR CAPTAIN CAPSLOCK

CANT READ YOUR CODE. BUT PEOPLE CONTINUE USING COMMANDS WITHOUT READING THE DOCUMENTATION. TRY MIN(D(:)) OR MIN(MIN(D)). THIS WILL PROBABLY NOT WORK SINCE YOU WOULD HAVE TO DEACTIVATE CAPS LOCK

[Niels]

About editing your question. It was all about the sentence after your code which is still unreadable since you did not use {}code. In your for loop you overwrite c 2 times. Hence c is a vector and no matrix. Preallocate c as 3x3 array

c=zeros(3,3); for i=1:m-1 c(i,:)=... end MinimumOfaMatrix=min(c(:));

Dont use x as index pls... and maybe add a question