# to select consecutive more than one column in matlab having difference

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Safi ullah il 26 Feb 2017
Modificato: Stephen23 il 26 Feb 2017
Hello everyboby, I have a matrix named eta=54×1800.for selecting specific rows and columns typically we used e.g result=eta(:, 86:90:1800); But here I need to select consecutive 5 columns 86,87,88,89,90 each having difference 90, e.g after 86,87,88,89,90 I want to get 176,177,178,179,180.I try like result=eta(:,[86:90:1800,87:90:1800,88:90:1800,89:90:1800,90:90:1800]); but it does not give the result of consecutive columns.
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Stephen23 il 26 Feb 2017
Modificato: Stephen23 il 26 Feb 2017
Sort the indices to get consecutive columns adjacent to each other:
idx = sort([86:90:1800,87:90:1800,88:90:1800,89:90:1800,90:90:1800])
eta(:,idx)
Or without having to write that long list:
>> vec = 86:90;
>> C = arrayfun(@(b)b:90:1800, vec, 'Uni',0);
>> idx = sort([C{:}])
or generate them in the correct order in the first place:
>> vec = 86:90;
>> idx = bsxfun(@plus,vec(:),0:90:1800-90);
>> idx = idx(:).'
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