How can we find the non common strings from multiple columns
    6 visualizzazioni (ultimi 30 giorni)
  
       Mostra commenti meno recenti
    
Dear all,
I want to compare the following three columns of strings (of different length) and find the entries that are NOT common across them. Just to mention that my real vectors (listA,listB,listC, etc) are of large size.
    listA={'India'
    'Iran'
    'Ireland'
    'Israel'
    'Jordan'
    'Kuwait'
    'Lebanon'
    'Lesotho'
    'Libya'
    'Luxembourg'
    'Malawi'
    'Maldives'
    'Morocco'
    'Nepal'
    'Netherlands'
    'Norway'
    'Oman'
    'Paraguay'
    'Peru'
    'Philippines'
    }; listB={    'Denmark'
    'El Salvador'
    'Gabon'
    'Gambia'
    'Lebanon'
    'Lesotho'
    'Libya'
    'Luxembourg'
    'Malawi'
    'Maldives'
    'Morocco'
    'Nepal'
    'Netherlands'
    'Norway'
    'Oman'
    'Paraguay'
    'Peru'
    'Philippines'
    'Qatar'
    'Rwanda'
    'Saudi Arabia'
    'Senegal'
    'Singapore'
    'Sudan'}; listC= {'Kuwait'
    'Lebanon'
    'Lesotho'
    'Nepal'
    'Netherlands'
    'Oman'
    'Sweden'
    'Syria'
    'Tanzania'
    'Turkey'
    'Uruguay'};
    Risposta accettata
  Stephen23
      
      
 il 13 Mar 2017
        
      Modificato: Stephen23
      
      
 il 13 Mar 2017
  
      First lets find the strings that are common to all cell arrays:
listA={'India','Iran','Ireland','Israel','Jordan','Kuwait','Lebanon','Lesotho','Libya','Luxembourg','Malawi','Maldives','Morocco','Nepal','Netherlands','Norway','Oman','Paraguay','Peru','Philippines',};
listB={'Denmark','El Salvador','Gabon','Gambia','Lebanon','Lesotho','Libya','Luxembourg','Malawi','Maldives','Morocco','Nepal','Netherlands','Norway','Oman','Paraguay','Peru','Philippines','Qatar','Rwanda','Saudi Arabia','Senegal','Singapore','Sudan'};
listC={'Kuwait','Lebanon','Lesotho','Nepal','Netherlands','Oman','Sweden','Syria','Tanzania','Turkey','Uruguay'};
%
lists = {listA,listB,listC}; % storing data together makes working with them much simpler.
%
exc = lists{1};
for k = 2:numel(lists)
    exc = intersect(exc,lists{k});
end
giving the strings found in all cell arrays as:
 exc =
    'Lebanon'
    'Lesotho'
    'Nepal'
    'Netherlands'
    'Oman'
Now we can easily get the input cell arrays with the strings from exc removed:
out = cell(size(lists));
for k = 1:numel(lists)
    out{k} = setdiff(lists{k},exc);
end
giving:
>> out{:}
ans = 
    'India' 'Iran' 'Ireland' 'Israel' 'Jordan' 'Kuwait' 'Libya' 'Luxembourg' 'Malawi' 'Maldives' 'Morocco' 'Norway' 'Paraguay' 'Peru' 'Philippines'
ans =
    'Denmark' 'El Salvador' 'Gabon' 'Gambia' 'Libya' 'Luxembourg' 'Malawi' 'Maldives' 'Morocco' 'Norway' 'Paraguay' 'Peru' 'Philippines' 'Qatar' 'Rwanda' 'Saudi Arabia' 'Senegal' 'Singapore' 'Sudan'
ans =
    'Kuwait' 'Sweden' 'Syria' 'Tanzania' 'Turkey' 'Uruguay'
And if you want a list of all strings together, excluding those in exc:
uni = {};
for k = 1:numel(lists)
    uni = union(uni,lists{k});
end
uni = setdiff(uni,exc)
gives:
uni =
    'Denmark' 'El Salvador' 'Gabon' 'Gambia' 'India' 'Iran' 'Ireland' 'Israel' 'Jordan' 'Kuwait' 'Libya' 'Luxembourg' 'Malawi' 'Maldives' 'Morocco' 'Norway' 'Paraguay' 'Peru' 'Philippines' 'Qatar' 'Rwanda' 'Saudi Arabia' 'Senegal' 'Singapore' 'Sudan' 'Sweden' 'Syria' 'Tanzania' 'Turkey' 'Uruguay'
Più risposte (1)
Vedere anche
Categorie
				Scopri di più su Modulation in Help Center e File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!