Matrix mapping in order to get its elements in binary form.

I have a matrix with columns and rows having indices on it. Is it possible to create the matrix from same provided matrix in binary form. For example.1st row 1st column of the matrix in 29. Is it possible by any chance I can get 1 or 0 here.

    M = [ 29    22    15     8
          37    30    23    16
          45    38    31    24
           1    46    39    32
           5     1    47    40
          13     6     1    48
          21    14     7     1 ];

[kritika adhikari]

This is 8 by 4 matrix.

[per isakson]

• What do you mean by "binary"?
• What about &nbsp B=(M&gt=21); ?

[kritika adhikari]

Actually I have a matrix with indices on it. Is there any way (mapping) so that I can get my matrix with 1 and 0 on it. It doesnot mean converting 8 to binary form.

Answer 1

[Image Analyst]

Try this:

m=[...
  29    22    15     8
  37    30    23    16
  45    38    31    24
  1    46    39    32
  5     1    47    40
  13     6     1    48
  21    14     7     1]
[rows, columns] = size(m)
for col = 1 : columns
  for row = 1 : rows
    caM{row, col} = dec2bin(m(row, col));
  end
end
caM % Print to command window

The results:

caM =
  7×4 cell array
    '11101'     '10110'     '1111'      '1000'  
    '100101'    '11110'     '10111'     '10000' 
    '101101'    '100110'    '11111'     '11000' 
    '1'         '101110'    '100111'    '100000'
    '101'       '1'         '101111'    '101000'
    '1101'      '110'       '1'         '110000'
    '10101'     '1110'      '111'       '1'