Optimization for minimizing cylinder dimensions
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Hi there, I am hoping to verify my optimization calculations using Matlab for a cylinder's dimensions (inner (x2) and outer (x1) radius) with 2 constraint equations (max bending and deflection).
The function (objfun.m) was inputed as:
function f=objfun (x)
f=(3667.81*x(1)^2)-(3667.81*x(2)^2);
end
The constraint (constraints.m) was inputed as:
function[c,ceq]=constraints(x)
c=[-30*10^6+(31.23*(x(1)^2-x(2)^2)^(-1))+(58.33*x(1)*(x(1)^4-x(2)^4)^(-1));-0.005+(6.23591*10^(-11)*(x(1)^4-x(2)^4)^(-1))];
ceq=[];
end
My optimum (Optimum.m) script is as follows:
clc
clear all
warning off
x0=[0,0];
f=objfun(x0);
[c,ceq]=constraints (x0);
options=optimset('LargeScale', 'off');
[x,fval]=fmincon(@objfun,x0,[],[],[],[],@constraints, options);
[c,ceq]=constraints (x);
But when it is run I end up with the following:
Error using fmincon (line 220)
FMINCON requires the following inputs to be of data type double: 'LB','UB'.
Error in Optimum (line 8)
[x,fval]=fmincon(@objfun,x0,[],[],[],[],@constraints, options);
Any insight and assistance would be greatly appreciated. I have also attempted to use the Optimization tool in Matlab with no results yet, so if anyone is comfortable with that App I would love to learn it. Thank you
0 Commenti
Risposte (1)
Alan Weiss
il 19 Mar 2017
Modificato: Alan Weiss
il 19 Mar 2017
You missed counting the fmincon input arguments. Try this instead:
[x,fval] = fmincon(@objfun,x0,[],[],[],[],[],[],@constraints,options);
Two hints to help in the future:
1. Try defining ALL the fmincon arguments, even the ones you don't use. Such as
A = [];
b = [];
Aeq = [];
beq = [];
lb = [];
ub = [];
[x,fval] = fmincon(@objfun,x0,A,b,Aeq,beq,lb,ub,@constraints,options);
2. Next time you want to ask a question and provide your code, use the {} Code button to make it look better (doesn't the code in my answer look better than that in your question?)
Alan Weiss
MATLAB mathematical toolbox documentation
2 Commenti
Torsten
il 20 Mar 2017
If x(1) and x(2) are both zero at the beginning, you divide by zero in the constraint function.
Choose a different initial guess for x.
Best wishes
Torsten.
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