Creating an array based off column value
6 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
I have an array, size 8809x3, that I would like to separate into three independent arrays based off of the value in Column 3.
Column 3 is either a 1, 2, or 3. So I would like to create three arrays, each of which only contain the rows of 1's, 2's, and 3's.
I have tried to use if statements and for loops, none of which I have been able to get to work. Do any of you know how I can do this?
0 Commenti
Risposta accettata
Stephen23
il 29 Mar 2017
Modificato: Stephen23
il 29 Mar 2017
Use logical indexing:
>> A = randi(3,5,3);
>> X = A(A(:,3)==1,:);
>> Y = A(A(:,3)==2,:);
>> Z = A(A(:,3)==3,:);
Although it may be more efficient to keep your data together in one array and simply access the parts of the array when required. In general you should keep data together as much as possible, rather than trying to split it apart. For example you could easily split the array into a cell array of matrices:
>> accumarray(A(:,3),1:size(A,1),[],@(n){A(n,:)})
ans =
[1x3 double]
[2x3 double]
[2x3 double]
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Matrices and Arrays in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!