Rehsaping Data Table to new format

Hi, I have a data table that exists like:
[date] [field] [data]
1/1/2017 A 1
1/2/2017 A 2
1/3/2017 A 3
1/1/2017 B 3
1/2/2017 B 2
1/3/2017 B 1
1/1/2017 C 4
1/2/2017 C 5
1/3/2017 C 6
and i want to reshape the data to be like this:
[Date] [A] [B] [C]
1/1/2017 1 3 4
1/2/2017 2 2 5
1/3/2017 3 1 6
so that each unique value in fields becomes a new field name in the new table.
I saw this conversion done in a tutorial the other day, but cant recall how it was done at all, thanks for any input in advance!
Matt

 Risposta accettata

I think you are looking for unstack:
>> t = cell2table( ...
{'1/1/2017', 'A', 1; ...
'1/2/2017', 'A', 2; ...
'1/3/2017', 'A', 3; ...
'1/1/2017', 'B', 3; ...
'1/2/2017', 'B', 2; ...
'1/3/2017', 'B', 1; ...
'1/1/2017', 'C', 4; ...
'1/2/2017', 'C', 5; ...
'1/3/2017', 'C', 6},'VariableNames',{'date' 'field' 'data'});
>> t.date = datetime(t.date,'InputFormat','MM/dd/yyy');
>> t.field = categorical(t.field)
t =
9×3 table
date field data
___________ _____ ____
01-Jan-2017 A 1
02-Jan-2017 A 2
03-Jan-2017 A 3
01-Jan-2017 B 3
02-Jan-2017 B 2
03-Jan-2017 B 1
01-Jan-2017 C 4
02-Jan-2017 C 5
03-Jan-2017 C 6
>> t2 = unstack(t,'data','field')
t2 =
3×4 table
date A B C
___________ _ _ _
01-Jan-2017 1 3 4
02-Jan-2017 2 2 5
03-Jan-2017 3 1 6

Più risposte (2)

Steven Lord
Steven Lord il 7 Apr 2017

0 voti

If your data is stored in a table or timetable, use unstack. The first example on that documentation page is pretty close to the exact scenario you gave, so it should be easy to adapt for your needs.
Matt
Matt il 10 Apr 2017

0 voti

Both answer the question and accomplish what i was looking to do, thanks very much!

Tag

Richiesto:

il 7 Apr 2017

Risposto:

il 10 Apr 2017

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