Replacing each array element with a series of values
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Hi, I have a a 1 x N matrix of numbers. For example, a matrix T:
T = [1 4 7]
I would like to convert T to the new matrix as follows:
T_new = [1 2 3 4 5 6 7 8 9]
Basically, each element of T is replaced by an arithmetic series of 3 values with that element as the starting element and common difference = 1.
I tried
T_new = [T:T+3];
But it only updates the first element (I get T_new = [1 2 3 4]). Is there any quick way to do this without using a for loop ?
Thanks.
0 Commenti
Risposta accettata
Stephen23
il 25 Apr 2017
>> T = [1,4,7];
>> cell2mat(arrayfun(@(n)n+(0:2),T,'uni',0))
ans =
1 2 3 4 5 6 7 8 9
0 Commenti
Più risposte (2)
Andrei Bobrov
il 25 Apr 2017
Modificato: Andrei Bobrov
il 25 Apr 2017
T_new = reshape(T(:)' + (0:2)',1,[])
3 Commenti
Andrei Bobrov
il 26 Apr 2017
You are using an older version of MATLAB.
Variant for you:
T_new = reshape(bsxfun(@plus,T(:)',(0:2)'),1,[])
dbmn
il 25 Apr 2017
One possible solution would be:
0. having
T = [1 4 7];
1. create a temporary matrix T_temp that looks like (this could be done in a loop very easily)
T_new = [1 2 3;
4 5 6;
7 8 9 ];
2. then reshape that matrix using
T_new=reshape(T_tmp', 1, numel(T_tmp));
1 2 3 4 5 6 7 8 9
Vedere anche
Categorie
Scopri di più su Loops and Conditional Statements in Help Center e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!