multiple area with different base values

Is it possible to show multiple area in a graph with different base values ? In the following example, the base value of the first area is changing when the second one is displayed.
figure
x = linspace(0,2*pi);
y = sin(x);
plot(x,y,'linewidth',2);
hold on;
f = y>=0.9;
h(1) = area(x(f),y(f),...
'BaseValue',0.9,...
'ShowBaseLine','off',...
'FaceColor','red',...
'FaceAlpha',0.2,...
'LineStyle','none');
fprintf('basevalue: %.2f\n',h(1).BaseValue);
f = y<=-0.3;
h(2) = area(x(f),y(f),...
'BaseValue',-0.3,...
'ShowBaseLine','off',...
'FaceColor','green',...
'FaceAlpha',0.2,...
'LineStyle','none');
fprintf('basevalue: %.2f\n',h(1).BaseValue);
Thanks for the help ! (Matlab R2016b)

1 Commento

One way to bypass this issue :
figure
x = linspace(0,2*pi);
y = sin(x);
plot(x,y,'linewidth',2);
hold on;
bv = 0.9;
f = y>=bv;
ybv = repmat(bv,1,sum(f));
h = area([x(f);x(f)]',[ybv;y(f)-ybv]',...
'ShowBaseLine','off',...
'FaceColor','red',...
'FaceAlpha',0.2,...
'LineStyle','none');
delete(h(1));
f = y<=-0.3;
h2 = area(x(f),y(f),...
'BaseValue',-0.3,...
'ShowBaseLine','off',...
'FaceColor','green',...
'FaceAlpha',0.2,...
'LineStyle','none');
but...

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Risposte (2)

Manish Annappa
Manish Annappa il 19 Mag 2017
I compared the graphs generated from the above code snippets posted by you. The second code snippet seems to give the expected results. Any reason why this solution is not acceptable to you?

1 Commento

Indeed the second code snipped gives the expected results but is much less intuitive. Is is a bug or a feature to have only one BaseValue per axis ?

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Ullekh Gambhira
Ullekh Gambhira il 16 Giu 2018
I was facing a similar issue, solved it by using "Shade area between two curves" function by John Bockstege. The file exchange link for this function is below:
https://www.mathworks.com/matlabcentral/fileexchange/13188-shade-area-between-two-curves
It does not consider base value, but basically shades the area between two lines. So one line can be your vector and the other can be a baseline*ones(size(x)).
Hope this helps.
Regards, Ullekh

Richiesto:

il 17 Mag 2017

Risposto:

il 16 Giu 2018

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