Dipole antenna far-field pattern
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Vinci
il 22 Mag 2017
Risposto: Omkar Savkur
il 29 Giu 2021
I need to plot the radiation pattern for a dipole antenna of length L=lambda/2. The example plot given was of L=1.4*lambda.
Example plot of L=1.4*lambda:
My code to try and reproduce the plot for L=1.4*lambda:
%Wavelength
lam = 1;
%Dipole antanna
L = 1.4*lam;
%Phase constant
B = 2*pi/lam;
t = 0:0.01:2*pi;
% Far-field pattern equation
E = abs((cos(B*L/2*cos(t))-cos(B*L/2))./sin(t));
figure()
polar(t,E)
Plot from this code:
I can't figure out where I'm going wrong with this one...
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Risposta accettata
David Goodmanson
il 22 Mag 2017
Hi Vinci, power is proportional to the square of the electric field, so if you use
E2 = abs((cos(B*L/2*cos(t))-cos(B*L/2))./sin(t)).^2;
figure()
polar(t,E2)
the correct figure should pop up.
Più risposte (1)
Omkar Savkur
il 29 Giu 2021
Hi Vinci, building off David's answer, you can use the polarpattern function to help plot the radiation power. You can interact with the plot and specify the plot parameters all in one line.
% Wavelength
lam = 1;
% Dipole antanna
L = 1.4*lam;
% Phase constant
B = 2*pi/lam;
% Angle in degrees
t = 0:0.1:360;
% Far-field pattern equation
E = abs((cos(B*L/2*cosd(t))-cos(B*L/2))./sind(t)).^2;
figure(1)
polarpattern(t,E,'AngleResolution',30)
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