Azzera filtri
Azzera filtri

How to solve : Subscripted assignment dimension mismatch error

3 visualizzazioni (ultimi 30 giorni)
Dear guys I am new in MATLAB. It is a simple code which i make it. but i get this error message"Subscripted assignment dimension mismatch." I dont know whats the problem with that. would you please help me?
A=[]
A=randi(10,2,3)
for i=1:2
for j=1:3
if A(i,j)>3
A(i,j)='ok';
elseif A(i,j)==2
A(i,j)='no'
else
A(i,j)=' ';
end
end
end
  1 Commento
Stephen23
Stephen23 il 26 Mag 2017
Modificato: Stephen23 il 26 Mag 2017
A is a numeric array, which you then try to force non-scalar char vector into the elements of. It is not possible to put multiple array elements into one element of another array. If r and c are scalars, then:
X(r,c) = 1; % okay
X(r,c) = [1,2] % an error

Accedi per commentare.

Risposta accettata

bahar kh
bahar kh il 26 Mag 2017
still I have a question.when I change the code to the following form it works too.why? the last code and new one, almost are the same. but why the original code in my question doesn't work but the modified version works? what is the difference between them? thanks in advance
the modifiied version is here A=[] A=randi(10,2,3) for i=1:2 for j=1:3 if A(i,j)>3 A(i,j)=0; elseif A(i,j)==2 A(i,j)=2 else A(i,j)=6; end end end
  1 Commento
Andrei Bobrov
Andrei Bobrov il 26 Mag 2017
>> A=randi(10,2,3)
A =
9 2 7
10 10 1
>> A(1,1) = 2
A =
2 2 7
10 10 1
>> A(2,1) = 'no'
Assignment has more non-singleton rhs dimensions than non-singleton subscripts
>> double('no')
ans =
110 111
>>

Accedi per commentare.

Più risposte (1)

Andrei Bobrov
Andrei Bobrov il 26 Mag 2017
Use cell - array ( Aout) for output data in your function
A=randi(10,2,3);
Aout = cell(size(A);
for i=1:2
for j=1:3
if A(i,j)>3
Aout{i,j}='ok';
elseif A(i,j)==2
Aout{i,j}='no'
else
Aout{i,j}=' ';
end
end
end
  1 Commento
bahar kh
bahar kh il 26 Mag 2017
Modificato: bahar kh il 26 Mag 2017
thanks@Andrei Bobrov. It works for me. but still I have a question.when I change the code to the following form it works too.why? the last code and new one, almost are the same. but why the original code in my question doesn't work but the modified version works? what is the difference between them? thanks in advance
the modifiied version is here A=[] A=randi(10,2,3) for i=1:2 for j=1:3 if A(i,j)>3 A(i,j)=0; elseif A(i,j)==2 A(i,j)=2 else A(i,j)=6; end end end

Accedi per commentare.

Categorie

Scopri di più su Graphics Performance in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by