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how to average specific rows of all columns?

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i am having 100x32 matrix in my data set. i would like to average 20 rows of all columns, like first 20rows average, next 20 and so..on...
can any one help in this problem.

Risposta accettata

the cyclist
the cyclist il 10 Giu 2017
Modificato: the cyclist il 10 Giu 2017
If I understand your question correctly, you can use the movmean command:
% Some made-up data
A = rand(100,32);
N = 20;
movingAverageA = movmean(A,[(N-1) 0]); % Trailing average of N rows
output = movingAverageA(N:N:end,:);
  3 Commenti
Image Analyst
Image Analyst il 12 Giu 2017
Did you get it working? You've accepted this answer so I assume so.
laxminarayana pasupuleti
laxminarayana pasupuleti il 12 Giu 2017
in my version its not woking..so i am trying latest version...

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Più risposte (2)

J Yadav
J Yadav il 16 Gen 2019
to take a moving average of 1 to 20 rows, then 21-40 rows, then 41-60 rows etc.
of a data matrix with n rows and m columns.
you may also try:
for i=1:(n/20) % given that n is a multpile of 20 or your choice of no. of rows to average.
a=(i-1)*20+1;
b=(i-1)*20+20;
meandata(i,:) = mean(data(a:b,:),1);
end

Image Analyst
Image Analyst il 10 Giu 2017
Modificato: Image Analyst il 12 Giu 2017
The first index are the rows. For example to average only the first 20 rows
columnMeans = mean(data([1:20], :), 1);
Or to average rows 34, 23, and 194, do
rowsToAverage = [34, 23, 194];
columnMeans = mean(data(rowsToAverage, :), 1);
  2 Commenti
Image Analyst
Image Analyst il 12 Giu 2017
This seems to work:
data = randi(9, 100, 32) % Sample 100x32 data
columnMeans = [
mean(data([1:20], :), 1);
mean(data([21:40], :), 1);
mean(data([41:60], :), 1);
mean(data([61:80], :), 1);
mean(data([81:100], :), 1)]
Is that what you want?

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