calculate the function in vector.
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JaeSung Choi
il 12 Giu 2017
Commentato: JaeSung Choi
il 13 Giu 2017
I want to calculate my 'poly' function for domain of linspace(0,1,100) so I tried ---------------------------------
%make poly function
function [output] = poly(input)
output= ([input^0 input^1 input^2 input^3 input^4 input^5]*transpose([1.0000 1.0001 0.4991 0.1703 0.0349 0.0139]) )
end
----------------------------------
x = linsapce(0,1,100)
poly(x)
----------------------------------
but it doesn't work. I found that for sin(x) it does. I want to know what's different between to func. and how to solve the problem.
1 Commento
KSSV
il 12 Giu 2017
What is the input you used? You have to take care of element by element operations.
Risposta accettata
Andrei Bobrov
il 13 Giu 2017
Modificato: Andrei Bobrov
il 13 Giu 2017
function [output] = AsPolyvalForJaeSung(input)
output = bsxfun(@power,input(:),0:5)*[1.0000;1.0001;0.4991;0.1703;0.0349;0.0139];
end
Più risposte (2)
KSSV
il 12 Giu 2017
For
input = linspace(0,1,100) ;
In the line
output= ([input.^0 input.^1 input.^2 input.^3 input.^4 input.^5]*transpose([1.0000 1.0001 0.4991 0.1703 0.0349 0.0139]) )
The size of term in square braces would be 1X600 where as the term transpose i.e second term got only 6X1 terms. How you expect them to multiply? You need to rethink on your code.
Torsten
il 12 Giu 2017
output= ([(input.').^0 (input.').^1 (input.').^2 (input.').^3 (input.').^4 (input.').^5]*([1.0000 1.0001 0.4991 0.1703 0.0349 0.0139]).'
Best wishes
Torsten.
2 Commenti
Torsten
il 13 Giu 2017
??
According to your question, I think this is exactly what you needed.
Best wishes
Torsten.
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