Linear programming with complex inequalities

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I just wanna solve:
min Z=20X+18Y
with
2X+3Y>=10
4X+7Y>=28
X>=0, Y>=0
Answer is X=0, Y=4 and Z=72 How can i use the linprog command but with >= inequalities?

Risposta accettata

Torsten
Torsten il 14 Giu 2017
Multiply the >= inequalities by (-1).
Best wishes
Torsten.
  4 Commenti
Nik Sam
Nik Sam il 14 Giu 2017
f=[-20 -18]
A=[-2 -3;-4 -7]
B=[-10 -28]
Aeq=[];
beq=[];
lb=[0 0];
ub=[];
[x,fval,exitflag,output]=linprog(f,A,B,Aeq,beq,lb,ub)
Torsten
Torsten il 14 Giu 2017
f=[20 18]
Best wishes
Torsten.

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