datestr problem with minutes
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Hello everyone,
I'm encountering a problem with date conversion. I have a dataset column with dates in '1/5/2017 12:10:00AM' form and I want to convert it into '2017-05-01 00:10:00' format. I used the datestr function but the minutes are incorrect. All rows return with 00 minutes.
How can I fix this?
Thank you in advance, Vanessa
3 Commenti
Stephen23
il 29 Giu 2017
@Vanessa: please show us the code you have used and the data that causes this behavior.
Vanessa
il 29 Giu 2017
Andrei Bobrov
il 29 Giu 2017
Dear Vanessa! please accept the answers that solved your problems.
Risposte (2)
Walter Roberson
il 29 Giu 2017
t = datenum('1/5/2017 12:10:00AM' );
datestr(t, 'YYYY-mm-DD HH:MM:ss')
Andrei Bobrov
il 29 Giu 2017
Modificato: Andrei Bobrov
il 29 Giu 2017
a = datetime('1/5/2017 12:10:00AM','I','dd/MM/yyyy hh:mm:ssa','F','yyyy-MM-dd HH:mm:ss')
4 Commenti
Vanessa
il 29 Giu 2017
Walter Roberson
il 29 Giu 2017
You cannot. When you use datetime() all of the entries need to be in the same 'InputFormat' (that here was abbreviated as 'I'). If you know you have entries that are in a different format, you need to detect and process them.
For example:
a = datetime(StringArrayOfTimes, 'I', 'dd/MM/yyyy hh:mm:ssa','F','yyyy-MM-dd HH:mm:ss');
failed_on = isnat(a);
a(failed_on) = datetime(StringArrayOfTimes(failed_on), 'I', 'dd/MM/yyyy', 'F', 'yyyy-MM-dd HH:mm:ss');
The above does a patch-up pass, where it tries to re-interpret the failed times with the abbreviated format.
Vanessa
il 29 Giu 2017
Andrei Bobrov
il 29 Giu 2017
a = {'1/5/2017';
'1/5/2017 12:10:00AM';
'1/5/2017 12:15:00AM';
'1/5/2017 12:20:00AM';
'2/5/2017'};
t = ~cellfun(@isempty,regexp(a,'\d{4}$'));
a(t) = cellfun(@(x)[x,' 00:00:00AM'],a(t),'un',0);
out = datetime(a,'I','dd/MM/yyyy hh:mm:ssa','F','yyyy-MM-dd HH:mm:ss')
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