Calling a superclass method from any method

Hi,

I have a base class:

classdef foo < handle

    function methodA( self )

end

And a base class:

classdef goo < foo

    function methodA( self )
       if ( condition )
           self.methodA@foo();
       else
           other stuff
       end
    end

    function methodB( self )
       self.methodA@foo();
    end

end

Why isn't this possible ?

Every other langage allows it, I do not get the point. Is there any way to get it to work ?

I need A to be the public interface: the framework user is not allowed to bypass the override. However B is framework private, needed for internal management of values. So no, I cannot invert A & B in the child class nor I cannot rename A.

Answer 1

[Robert U]

Hi Zangdaar,

I am not sure if I got your point correctly. In my understanding you have two base classes where class_B has to invoke a method of class_A. Since I do not know what data you would like to share between the objects I introduce a random property.

Base class A:

 classdef class_A < handle;
   properties
   end

   methods
     function obj = methodA(obj)
       disp('<< Method A of class_A utilized!');
     end
   end
 end

Base class B:

 classdef class_B < handle;

   properties
     classA_Property
   end

   methods
     function obj = methodA(obj)
       disp('<< Method A of class_B utilized!');
       c = clock;
       disp(['<< actual seconds: ',num2str(fix(c(6)))])

       if mod(fix(c(6)),2) == 0
         TmpClassA = class_A;
         TmpClassA.methodA;

         obj.classA_Property = TmpClassA;
       else
         disp('<< methodA in class_B continued.');
       end
     end

        function obj = methodB(obj)
            disp('<< Method B of class_B utilized!');
            obj.methodA;
        end
    end
 end

In that case you create a temporary object of class_A on which you can utilize method_A of class_A that can have the same name as method_A in class_B.

Second option in my opinion is, to use class_A as superclass for class_B_inh_A. In that case it is possible to call the methodA of class_A that is shadowed by methodA of class_B_inh_A. The only thing is that it is not possible to call it from methodB which brings us back to the temporary class_A call:

 classdef class_B_inh_A < class_A;

   properties
     classA_Property;
   end

   methods
     function obj = methodA(obj)
       disp('<< Method A of class_B_inh_A utilized!');
       c = clock;
       disp(['<< actual seconds: ',num2str(fix(c(6)))])

       if mod(fix(c(6)),2) == 0;
         obj.methodA@class_A;
       else
         disp('<< methodA in class_B_inh_A continued.');
       end
     end

     function obj = methodB(obj)
       disp('<< Method B of class_B_inh_A utilized!');
       obj.methodA;

       TmpClassA = class_A;
       TmpClassA.methodA;

       obj.classA_Property = TmpClassA;
     end
   end

 end

Calling class_A method A:

 >> A = class_A;
 >> A.methodA;

<< Method A of class_A utilized!

Calling class B method A:

 >> B = class_B;
 >> B.methodA;

<< Method A of class_B utilized!

<< actual seconds: 45

<< methodA in class_B continued.

 >> B.methodA;

<< Method A of class_B utilized!

<< actual seconds: 52

<< Method A of class_A utilized!

Calling class B method B:

 >> B.methodB;

<< Method B of class_B utilized!

<< Method A of class_B utilized!

<< actual seconds: 24

<< Method A of class_A utilized!

<< Method A of class_A utilized!

 >> B.methodB;

<< Method B of class_B utilized!

<< Method A of class_B utilized!

<< actual seconds: 25

<< methodA in class_B continued.

<< Method A of class_A utilized!

Calling class B_inh_A method A:

 >> B_inh_A = class_B_inh_A;
 >> B_inh_A.methodA;

<< Method A of class_B_inh_A utilized!

<< actual seconds: 45

<< methodA in class_B_inh_A continued.

 >> B_inh_A.methodA;

<< Method A of class_B_inh_A utilized!

<< actual seconds: 46

<< Method A of class_A utilized!

Calling class B_inh_A method B:

 >> B_inh_A.methodB;

<< Method B of class_B_inh_A utilized!

<< Method A of class_B_inh_A utilized!

<< actual seconds: 53

<< methodA in class_B_inh_A continued.

<< Method A of class_A utilized!

 >> B_inh_A.methodB;

<< Method B of class_B_inh_A utilized!

<< Method A of class_B_inh_A utilized!

<< actual seconds: 54

<< Method A of class_A utilized!

<< Method A of class_A utilized!

Answer 2

[Zangdaarr]

Hey I'm really sorry, I made a typo in my example, so, Goo inherit Foo. Otherwise the question is pointless :/

Thanks a lot however for the long and detailed answer.