Compare arrays to find common non zero indexes

Hey I have one 2d and one cell array like this:

A=[14, 1, 0,15;
    1, 2, 4, 0;
    3, 0, 0, 0;
   14, 5, 0, 0;
    0,12, 4, 0]
x={[2,3,4,5];[1,3,4,5];[1,2,4,5]}

I want to find common non-zero elements in A based on X.

For example, firstly x{1,1}=[2,3,4,5] will be compared with A. As it is x{1,1} so all elements of x will be compared with 1st row in A. (first comparison will be row 1 and row 2 in A and common non zero index are 1 & 2 then next row 1 and row 3 and common non-zero index is 1 and similarly row 4 and row 5 will be compared) Then in same way for x{2,1} comparison will be between row 2 and rows 1,3,4 and 5 of A.

Thanks in advance

[Jan]

What have you tried so far? Which problems occurred? What is the wanted output for this example?

I do not understand:

 (first comparison will be row 1 and row 2 in A and common non zero
 index is 2 then next row 1 and row 3 and common non-zero indexes are
 1 and 2 and similarly row 4 and row 5 will be compared)

[lucksBi]

I have edited my question.. Sorry for confusion

Answer 1

[Jan]

A=[14, 1, 0,15;
    1, 2, 4, 0;
    3, 0, 0, 0;
   14, 5, 0, 0;
    0,12, 4, 0];
x = {[2,3,4,5]; [1,3,4,5]; [1,2,4,5]};
result = cell(size(x));
for k = 1:numel(x)
  Ak = A(k, :);     % Specified row
  xk = x{k};
  D  = cell(1, numel(xk));
  for r = 1:numel(xk)
     D{r} = find(Ak & A(xk(r), :));   % Or: Ak .* A(xk(r), :)
  end
  result{ix} = D;
end

UNTESTED

[lucksBi]

Hey thanks for your answer. Sorry for not making it clear. I want result in this form:

result{1,1}={[1,2],[1],[1,2],[2]};

result{2,1}={[1,2],[1],[1,2],[2,3]};

result{3,1}={1,1,1,0};

In result{1,1} i have to compare 1st row of A with all rows specified in x. So firstly i will compare row 1 with row 2 and common non zero indexes are 1,2 then next comparison is row 1 and row 3 and common non zero index is 1 and so on.

[Jan]

I've edited the answer. Does it create the wanted output?

[lucksBi]

Yes thanks alot for helping.