Result of z+conj(z) and z*conj(z) with z complex by default

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Gennaro Arguzzi
Gennaro Arguzzi il 7 Ago 2017
Modificato: John D'Errico il 7 Ago 2017
Hello everyone. Is it possible to get z+conj(z)=2*Re(z) and z*conj(z)=(abs(z))^2 without defining z=a+1i*b? I tried to wrote:
close all
clear all
syms z %z complex by default
z+conj(z) %result z+conj(z)
z*conj(z) %result z*conj(z)
Thank you in advance.

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John D'Errico
John D'Errico il 7 Ago 2017
Modificato: John D'Errico il 7 Ago 2017
Absolutely impossible. ;)
But why not try it?
syms z
simplify(z+conj(z))
ans =
2*real(z)
simplify(z*conj(z))
ans =
abs(z)^2
Surely it is always worth a try?

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