Finding Jacobian matrix for Newton's method
5 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Jenn Lee
il 13 Apr 2012
Commentato: Walter Roberson
il 8 Ago 2019
I have a very basic newton's method that uses a loop and:
y = Jac(x)\(-F(x));
x = x + y;
to solve for the approximate solution.
Where x is a the initial guess in the form of a vector, F is the nonlinear function, and Jac is the jacobian matrix. Currently, I am inputting the jacobian by hand.
For example, system of equations =
2x(1) + x(2)
3x(1) + x(2)^2
=> Jac(x) =
[2, 1; 3, 2x(2)]
I was wondering if instead of solving it by hand if I could get Matlab to do it for me.
0 Commenti
Risposta accettata
Walter Roberson
il 13 Apr 2012
If you have the symbolic toolbox you can use the jacobian() function.
2 Commenti
Walter Roberson
il 8 Ago 2019
x = sym('x', [1 2]);
eqn = [2*x(1) + x(2)
3*x(1) + x(2)^2];
jacobian(eqn, x)
Più risposte (1)
DIPANKAR POREY
il 7 Ago 2019
2x(1) + x(2)
3x(1) + x(2)^2
=> Jac(x) =
[2, 1; 3, 2x(2)]
1 Commento
Walter Roberson
il 8 Ago 2019
This does not appear to be an answer? It appears to be a copy of part of the question.
Vedere anche
Categorie
Scopri di più su Systems of Nonlinear Equations in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!