Unexpected Matlab Expression ?

I am new to coding and am unsure why my code does not work it says "Unexpected MATLAB expression" for the 3 in my code.
This is my code E(x)= [-1 1] 3 . * exp (1) . ^ ((-x)./4)
Any help is appreciated

4 Commenti

Jose Marques
Jose Marques il 11 Set 2017
Should be something between [-1 1] and 3.* ? What this represents?
Jose Marques
Jose Marques il 11 Set 2017
Maybe it is better to explain what the expression means.
it is supposed to be an envelope to another function, I have tried to add .* in between but that comes up as unexpected MATLAB Operator
I am supposed to code the function E(x)= plus or minus 3e^(-x/4)

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 Risposta accettata

Jose Marques
Jose Marques il 11 Set 2017
Natalie, try this:
E= [-1 1] * 3 *( exp (1) .^ ((-x)/4))
E will be a matrix 1x2 that first element is positive value and second will be the negative value

7 Commenti

When that is put in it says that the Matrix dimensions must agree
Jose Marques
Jose Marques il 11 Set 2017
Are you using the matrix E after that? Post you intire code; thus, we can be helpfull
Natalie Brehaut
Natalie Brehaut il 11 Set 2017
Modificato: Natalie Brehaut il 11 Set 2017
Trial>> x= 1: 0.1 : 10; Trial>> y= 3 . * exp (1) .^ ((-x)/4) . * sin (2 . * x) y= 3 . * exp (1) .^ ((-x)/4) . * sin (2 . * x) ↑ Error: Unexpected MATLAB operator.
Trial>> E= [-1 1] * 3 *( exp (1) .^ ((-x)/4)) Error using * Inner matrix dimensions must agree.
I am just very lost in what is wrong with my codes
Jose Marques
Jose Marques il 11 Set 2017
A tip: you must use .* to element wise multiplication: https://www.mathworks.com/help/matlab/ref/times.html
Natalie, have you ever use the for loop? Do you just wanna two values for E?
x=1:0.1:10;
for i=1:size(x,2)
y(i) = 3 * exp (1) .^ ((-x(i))/4) * sin (2 * x(i));
E= [-1 1] * 3 *( exp (1) .^ ((-x(i))/4));
end
plot(y)
THAT WORKED THANK YOU SO MUCH
Jose Marques
Jose Marques il 11 Set 2017
Nice work!

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