Azzera filtri
Azzera filtri

Code some excel formulas in Matlab, in a smart way

1 visualizzazione (ultimi 30 giorni)
Hey
I have a quick question, I have this excel ark where there is a column that has the following code:
q1 = 1/2 * x1 * y1
q2 = 1/2 * x2 * y2 + x1 * y1
q3 = 1/2 * x3 * y3 + x2 * y2 + x1 * y1
q4 = 1/2.............
and so on and so on.
How do I program this smart? I've tried to make a for loop, but I can't figure out how the make the 1/2 only stick to the new x-y values and not the others.

Risposta accettata

Steven Lord
Steven Lord il 11 Set 2017
This sounds vaguely homework-like so I'm not going to give the answer just a hint. I assume x1, x2, etc. refer to elements of a vector x and similarly for y1, y2, etc. Let xy be x.*y. Take a look at the cumsum function applied to xy. It doesn't get you all the way to your answer, but it gets you most of the way there.
  2 Commenti
Mikkel Ibsen
Mikkel Ibsen il 11 Set 2017
I've tried to work around some loops instead, but is the cumsum more efficient code?
This is what i have:
x = ([9;8;9;10;10]);
y = ([1;1;1;1;1]);
qadd = x.*y;
for i = 1:length(x)
q(i,1) = 0.5*qadd(i)+sum(qadd(1:i-1));
end
How would that look like in a cumsom?
José-Luis
José-Luis il 11 Set 2017
Modificato: José-Luis il 11 Set 2017
dummy = x.*y; %doesn't make much sense if y is a vector of ones
result = cumsum(dummy) - dummy./2;

Accedi per commentare.

Più risposte (1)

KL
KL il 11 Set 2017
x = 1:5;
y = 6:10;
xy = arrayfun(@(a,b) [x(1):a;y(1):b],x,y,'UniformOutput',false);
q = cellfun(@(c) sum([0.5 ones(size(c)-1)].*prod(c)),xy,'UniformOutput',false)
  2 Commenti
Mikkel Ibsen
Mikkel Ibsen il 11 Set 2017
I can see it works, but I have no idea what is going on, and at the same time the results are cells, which I don't understand to use on further coding, is there a way to make it into a double ?
Image Analyst
Image Analyst il 11 Set 2017
There is a mat2cell() function. See the FAQ http://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F for an explanation of cells. However I think Steven's answer/hint is the more straightforward, less cryptic approach.

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by