How can I isolate data from a matrix without a for loop?
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Dear all
given the matrix
M = rand(1000,10);
pre_indices = [ 40 60 70]
post_indices = [45 65 75]
I would like to isolate the following chunks from M
for i = 1:length(pre_indices)
M(pre_indices(i):post_indices(i),:)
end
could it be done without the loop? all chunks have the same dimensions
best regards MF
1 Commento
Guillaume
il 15 Set 2017
It's debatable whether using accumarray or arrayfun and co. can be considered to be without a loop. Yes, it's not a for loop but all these functions mean more or less the same: "loop over the data and do the same thing to each element".
In your case, the loop may be the clearest and fastest way to obtain what you want.
Risposte (2)
Andrei Bobrov
il 15 Set 2017
Modificato: Andrei Bobrov
il 15 Set 2017
M = (1:100)'*ones(1,5);
pre_indices = [ 40 60 70];
post_indices = [45 65 75];
n = (1:size(M,1))';
l = (n >= pre_indices(:)' & n <= post_indices(:)')*(1:numel(pre_indices))';
out = accumarray(l(l>0),n(l>0),[],@(x){M(x,:)});
or
n = (1:size(M,1))';
l = (n >= pre_indices(:)' & n <= post_indices(:)').*n;
out = M(l(l>0),:);
or
n = (1:size(M,1))';
l = any(n >= pre_indices(:)' & n <= post_indices(:)',2);
out = M(l,:);
if you have older version of MATLAB (< R2016b)
n = (1:size(M,1))';
k = bsxfun(@ge,n,pre_indices(:)') & bsxfun(@le,n,post_indices(:)');
l = k*(1:numel(pre_indices))';
out = accumarray(l(l>0),n(l>0),[],@(x){M(x,:)});
or
l = bsxfun(@times,k,n);
out = M(l(l>0),:);
or
out = M(any(k,2),:);
Guillaume
il 15 Set 2017
arrayfun(@(si, ei) M(si:ei, :), pre_indices, post_indices, 'UniformOutput', false)
This is most likely slower than the explicit loop, and for all intents and purposes is a loop.
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