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How to get rid of repeating values inside an array

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I have a matrix
a=[1 2 3 3 4 4 5];
I want to get rid of values 3 and 4 as they are repeating so that the output becomes
b=[1 2 5]

Risposta accettata

José-Luis
José-Luis il 19 Set 2017
Modificato: José-Luis il 19 Set 2017
b = a(sum(bsxfun(@eq,a,a'))==1)
  2 Commenti
José-Luis
José-Luis il 19 Set 2017
Modificato: José-Luis il 19 Set 2017
My pleasure.
Please keep in mind that this is inefficient for large arrays though. Just using unique() should take you where you need to go.

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Più risposte (1)

Andrei Bobrov
Andrei Bobrov il 19 Set 2017
Modificato: Andrei Bobrov il 21 Set 2017
v = unique(a);
b = v(histcounts(a,[v(:);v(end)+eps]) == 1);
or
v = unique(a);
b = v(histc(a,v) == 1);
or
aa = sort(a);
t = diff(aa);
b = aa([1 t] & [t 1]);
  3 Commenti
José-Luis
José-Luis il 19 Set 2017
histcounts() was introduced with R2014b. You don't need it though. unique() is enough. Andrei was giving you two alternatives.

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