how to calculate for each column

I want to calculate the value for each column

    A=[1 -8 5 -7;2 1 -1 1;-9 2 3 -8]
   zerocoeff=[];%intialising
  for k=1:10
  mid=23/4-length(zerocoeff);     %..eqn1
  mid(zerocoeff)=0;
  for i=1:3
  for j=1:4
  zerocoeff(i,j)=(A(i,j)<=0);    %......eqn2
  end

initially it should calculate with length(zerocoeff)=0 to calculate mid value and then after first iteration overwrite mid value with column wise length(zerocoeff)

[Jan]

@kitty: You forgot to ask a question. It is not efficient to let the readers guess the intention of the code and the problem you might have with it.

You are not a newcomer in the forum. Please remove the "if true ... end" from the code. It is polite to post proper code. Thanks.

The line

zerocoeff=[];%intialising

is useless: You overwrite the contents in the next line. Simply omit it.

[Walter Roberson]

I see that you have revised the code and explained more, but I do not know what question you are asking? Are you not already calculating for each column in your "for j" loop? Do you need to do something more than reversing the order of "for i" and "for j" ?

Answer 1

[Walter Roberson]

Guessing about what you are doing:

zerocount =  sum(A == 0);
mi = 5 - zerocount;