How to sort a matrix based on one index I have ?

3 visualizzazioni (ultimi 30 giorni)
t= [ 4 2
2 6
6 9]
c= [ 2
3
1]
Now, I want to arrange t according to c index; I need to get t nex sorted based on c :
t= [ 2 6
4 2
6 9]
Here is what I tried:
h=cell(1,1);
h{1,1}=t;
h{1,1}(c)
The answer I get is just one column sorted, but not the total matrix t.

Risposta accettata

Cedric
Cedric il 22 Ott 2017
Modificato: Cedric il 22 Ott 2017
I guess/hope that you made a mistake when you built your example of sorted t (that seems to be sorted according to c=[2;1;3]). If so, the solution should be:
t_sorted = t(c,:) ;

Più risposte (1)

Image Analyst
Image Analyst il 22 Ott 2017
You need to negate c and add 4 if you want the results you gave:
t= [ 4 2
2 6
6 9]
c= [ 2
3
1]
c2 = -c+4
h = t(c2,:)
You'll see:
h =
2 6
4 2
6 9
exactly as you requested. However, I think you may really want Cedric's solution, despite what you actually asked for.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by