how can i solve problem in my code for adaptive median filter

10 visualizzazioni (ultimi 30 giorni)
function f= dd(r,Smax)
if (Smax <= 1) | (Smax/2 == round(Smax/2)) | (Smax ~= round(Smax))
error('SMAX must be an odd integer > 1.')
end
[M, N] = size(r);
% Initial setup.
f = r;
f(:) = 0;
alreadyProcessed = false(size(r));
%Begin filtering.
for k = 3:2:Smax
zmin = ordfilt2(r, 1, ones(k, k), 'symmetric');
zmax = ordfilt2(r, k * k, ones(k, k), 'symmetric');
zmed = medfilt2(r, [k k], 'symmetric');
processUsingLevelB = (zmed > zmin) & (zmax > zmed) & ...
~alreadyProcessed;
zB = (r > zmin) & (zmax > r);
outputZxy = processUsingLevelB & zB;
outputZmed = processUsingLevelB & ~zB;
f(outputZxy) = r(outputZxy);
f(outputZmed) = zmed(outputZmed);
alreadyProcessed = alreadyProcessed | processUsingLevelB;
if all(alreadyProcessed(:))
break;
end
end
% Output zmed for any remaining unprocessed pixels. Note that this
% zmed was computed using a window of size Smax-by-Smax, which is
% the final value of k in the loop.
f(~alreadyProcessed) = zmed(~alreadyProcessed);
  1 Commento
Daleel Ahmed
Daleel Ahmed il 28 Ott 2017
Modificato: Walter Roberson il 28 Ott 2017
Error using ordfilt2
Expected input number 1, A, to be one of these types:
double, single, uint8, uint16, uint32, uint64, int8, int16, int32, int64, logical
Instead its type was char.

Accedi per commentare.

Risposta accettata

Walter Roberson
Walter Roberson il 28 Ott 2017
You appear to be attempting to pass in characters for the first input to your function, the one named "r" here. That input must be numeric for this code to work.

Più risposte (1)

Zeeshan Salam
Zeeshan Salam il 24 Mar 2019
can u send me working of this algorithm and flowchart

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by