Azzera filtri
Azzera filtri

How can I call inside a function a file *.* ?

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I have a set of files with the same name and different extensions, let them be a.env, a.shd, a.arr . I have created a script which calls those files inside a function. Is it possible to set those files as variables so that i can use them whenever it is necessary? I have already used the function genvarname but only for the 'a'. I don't know what to do with the extensions. Can anyone help? Thanks in advance.
  1 Commento
Paschalis Garouniatis
Paschalis Garouniatis il 3 Nov 2017
I used the fileparts and uigetfile functions to store the filename as a variable and they worked. However when i call them inside a function i get error. For example :
%1st case
file='/home/raptor/Desktop/BELLHOP_LAB/Bellhop_results/Ray_trace/a.ray';
[filepath,name,ext]=fileparts(file);
plotray name; hold on
plotbty name; hold on
plotati name; hold off
%2nd case
shd_file=uigetfile('*.shd');
plotshd 'shd_file'; hold on
plotbty 'name'; hold on
plotati 'name'; hold off
In both cases the functions plotray, plotshd, ... do not recognize the filename stored in the variable but the variable.

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Walter Roberson
Walter Roberson il 3 Nov 2017
basename = 'a';
dinfo = dir( [basename, '.*'] );
filenames = {dinfo.name};
Now filenames is a cell array of existing file names all with the same basic name but with the different extensions.
  5 Commenti
Paschalis Garouniatis
Paschalis Garouniatis il 3 Nov 2017
Is it possible to convert your code for the 1st case in which i don't need the extension of the file? For the second case that i checked it worked.
Walter Roberson
Walter Roberson il 3 Nov 2017
%1st case
file='/home/raptor/Desktop/BELLHOP_LAB/Bellhop_results/Ray_trace/a.ray';
[filepath,name,ext]=fileparts(file);
plotray(name); hold on
plotbty(name); hold on
plotati(name); hold off
%2nd case
shd_file=uigetfile('*.shd');
plotshd(shd_file); hold on
plotbty(name); hold on
plotati(name); hold off

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