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Cellfun with too many outpus

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Jakub Matousek
Jakub Matousek il 10 Nov 2017
Chiuso: MATLAB Answer Bot il 20 Ago 2021
Hi
dynamika_skryte_vrstvy = @(x,W,b)(2/(1+exp(-(W*x+b)*lambda)))-1;
z = cellfun(@(neco) dynamika_skryte_vrstvy(x,neco,b), num2cell(W,2),'UniformOutput',false);
z = cell2mat(z);
This code leads to:
-1 -1 0,999502352199065 -1 -1 -1 -1
-1 -1 -0,913691998327500 -1 -1 -1 -1
-1 -1 0,706815080445750 -1 -1 -1 -1
-1 -1 -0,999998050022476 -1 -1 -1 -1
-1 -1 0,999996403912792 -1 -1 -1 -1
-1 -1 -0,963307663082817 -1 -1 -1 -1
-1 -1 -0,999985431635414 -1 -1 -1 -1
The third column is right output I don't know why it's giving me all other columns. I could just take the one column, but the problem is that it seems the right column is changing index based on x.... Can't say why it is at all. Can someone help, please?(W is random matrix, b is random vector)

Risposte (1)

Guillaume
Guillaume il 10 Nov 2017
I don't know why it's giving me all other columns
Because your dynamika_skryte_vrstvy function returns a row vector for the given inputs.
What are the sizes of W, x, b and lambda? At least one of these latter 3 must have 7 rows.
  1 Commento
Jakub Matousek
Jakub Matousek il 10 Nov 2017
I got it needed to do this:
z = cellfun(@(neco,neco2) dynamika_skryte_vrstvy(x,neco,neco2), num2cell(W,2),num2cell(b),'UniformOutput',false);
First time working with cellfun. Need to think more next time...

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