What does the colon operator (:) in MATLAB do?
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The code below is used to draw a simple octagon on the screen with the word stop in the middle.
My question is, can anyone explain what is happening in the top statement. (variable t). What does the (1:2:15)' do?
Also, for example, if I wanted to draw a circle on the screen, how would I modify this code to do so.
t = (1:2:15)'*pi/8;
x = sin(t);
y = cos(t);
fill(x,y,'r')
axis square off
text(0,0,'STOP','Color',[0 0 0],'FontSize',80,'FontWeight','bold','HorizontalAlignment','center')
title('Figure STOP')
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Più risposte (3)
the cyclist
il 21 Mar 2011
2 voti
x and y are being created via a "parameterization" through t. The variable t is running from 0 to 2pi (i.e. around the circumference of the circle), but it does so in eight discrete intervals. (That's why you get eight sides.)
If you breakpoint your code after the first line, you will see that t takes equally spaced values around the circle. (The "linspace" command would have been another way to do this.) The part "1:2:15" is the vector [1 3 5 7 9 11 13 15].
Alexander
il 14 Ago 2013
0 voti
Yes but it's been seen as := as well, what does that do?
2 Commenti
Jan
il 15 Ago 2013
At 1st this is a new question and not an answer of the original question. At 2nd ":=" might be seen anywhere, but not in valid Matlab code. In a mathematical context a ":=" means, that the left side is defined as the right side.
Image Analyst
il 15 Ago 2013
I'm not even sure that Alexander "Answered" the question he thought he was. His response is a total non sequiter.
Shray Gupta
il 7 Feb 2021
0 voti
n = [0:1/fs:t];
what does it mean
1 Commento
Prakash Gautam
il 27 Giu 2022
I believe 1/fs shows the time spaced for 0 to t.
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