Azzera filtri
Azzera filtri

How do i create a matrix of size 1 row and 1501 column, with values [1 -1 1 -1 1 -1.... etc

3 visualizzazioni (ultimi 30 giorni)
(countinuously 1 then -1 repeating.
thanks Dan

Risposte (3)

Bjorn Gustavsson
Bjorn Gustavsson il 1 Mag 2012
v = (-1).^(0:n);
HTH

Wayne King
Wayne King il 1 Mag 2012
One way:
x = ones(1,1501);
x(2:2:end) = -1*x(2:2:end);
Another way
y = repmat([1 -1],1,751);
y(end) = [];

Daniel Shub
Daniel Shub il 1 Mag 2012
[repmat([1,-1], 1, floor(1501/2)), 1]

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