Find average of only directly repeating values in array
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Niklas Hausmann
il 6 Dic 2017
Commentato: Niklas Hausmann
il 7 Dic 2017
I have an array with two columns, that I want to clean up by finding the average value of column 1 for each unique value in column 2.
A = [
1 0.1
2 0.2
3 0.2
4 0.4
5 0.2 ]
I tried the unique function but have problems with repeating values (here 0.2 in the last row), so that in the above example I would not just calculate the average of rows 2 and 3, but of 2, 3 and 5. Is there a way to calculate the average of rows 2 and 3 separately from row 5?
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Andrei Bobrov
il 7 Dic 2017
ii = [true;diff(A(:,2)) ~= 0];
out = [accumarray(cumsum(ii),A(:,1),[],@mean),A(ii,2)];
Più risposte (2)
Akira Agata
il 7 Dic 2017
If you have the Image Processing Toolbox, the following code can do that task.
% Sample data
A = [1 0.1;
2 0.2;
3 0.2;
4 0.4;
5 0.2;
6 0.2;
7 0.3];
% Find directly repeating values and assign group ID
idx = diff(A(:,2)) == 0;
idx = [idx; 0] | [0; idx];
group = bwlabel(idx);
% Calculate the average for each group ID
average = splitapply(@mean, A(idx,1), group(idx));
Roger Stafford
il 7 Dic 2017
Modificato: Roger Stafford
il 7 Dic 2017
[~,~,n] = unique(A(:,2));
av = accumarray(n,A(:,1),[],@mean);
Note: You should be careful about how the elements in second column of A are generated. Different methods which produce fractions can result in tiny differences due to different round-off errors in what would ordinarily be regarded as like amounts. These would appear in different groups in 'unique'.
As to your question, "Is there a way to calculate the average of rows 2 and 3 separately from row 5?", are you asking a second question here distinct from the first one, or are you somehow trying to figure how to achieve that first objective?
2 Commenti
Image Analyst
il 7 Dic 2017
Yeah, Niklas, and "each unique value" seems contradictory to "only directly repeating values". So which is it? What about .1 and .4? They are unique values but not repeated values, so how do you want to handle those? Do you want those values in the output or not? Please clarify.
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