How to find pattern in an array?

92 visualizzazioni (ultimi 30 giorni)
How to find a pattern from a numeric array?
For example, there is a numeric array B and pattern (or mask) A. How to get the pattern location found in B? 
 
>> A = [1 2 3];
>> B = [5,4,3,1,2,3,5,4,1,2,3,4,5];
 
Expected output: 4, 9
 

Risposta accettata

MathWorks Support Team
MathWorks Support Team il 5 Dic 2017
There is no built-in MATLAB function that performs the exact operation described.
However, you can use a single for-loop and the built-in "all" and "find" functions to create a custom function that will output the desired behavior:
>> function output = pattern(B, A)
>> SIZE = length(B) - length(A);
>> match = zeros(1, SIZE);
>> for i=1:SIZE
>> match(i) = all(B(i:i-1+length(A)) == A);
>> end
>> output = find(match == 1);
>> end
  1 Commento
gwoo
gwoo il 25 Mag 2022
As @claudio points out below in More Answers, strfind(B, A) does exactly what is requested.

Accedi per commentare.

Più risposte (1)

claudio
claudio il 14 Mag 2020
output = strfind(B,A);
  1 Commento
claudio
claudio il 14 Gen 2021
No exceptions. if you have a particular request you can submit it to evaluate the specific case
str = sprintf('Special string for \t Karel \t K');
pattern = sprintf('\t');
idxTab = strfind(str,pattern)
idxTab =
20 28

Accedi per commentare.

Categorie

Scopri di più su Loops and Conditional Statements in Help Center e File Exchange

Prodotti


Release

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by