Comparing images using morphological operations only
3 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
I have to detect numbers on license plate through comparing them with the digits numbers images, only using morphology, but i get stuck after segmenting the digits and while comparing both images "9 from plate & 9 original image" ANDing gives me partially wrong answer
% max = -99999;
% bothTrue = IMG & One;
% NumPixels = sum(bothTrue(:));
% if NumPixels>max
% max=NumPixels;
% Digit=1;
% end
and getting the near "Extent area" fails also
min=100000;
A=sqrt((0.4913)^2-Anum^2); //this number i observed from the extent of image of digit"1"
if A<min
Digit=1;
min=A;
end
So is there someway to solve it using morph and logical operations only?
2 Commenti
Stephen23
il 22 Dic 2017
@koks paul: this is not twitter. I removed the ugly # characters from your tags, and separated them correctly using commas.
Risposte (2)
Walter Roberson
il 22 Dic 2017
No. The calculation
A=sqrt((0.4913)^2-Anum^2);
is not a morphological calculation.
Morphological operations transform one matrix to another matrix, but morphological operations never make decisions about what the input or output matrices mean. You always need a non-morophological operation to interpret the results of the transformation.
Image Analyst
il 22 Dic 2017
I don't know how to do it using morphology (dilation, erosion, opening, and closing). You can do it using logical operations (and, or, exclusive or, not). Try using the Dice Sorensen coefficient (demo attached).
Vedere anche
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!