Azzera filtri
Azzera filtri

How to subtract mean along rows?

9 visualizzazioni (ultimi 30 giorni)
JFz
JFz il 5 Gen 2018
Commentato: JFz il 8 Gen 2018
Hi,
I have a matrix 100x120 and I can group along the rows by findgroups. Then I use mean_mat = splitapply(@mean, mat, G) to get the means along rows. How to subtract the mean from the original matrix from each group? That is: for each group I, get mat_i - mean_mat_i? Thanks.

Risposta accettata

Manan Mishra
Manan Mishra il 8 Gen 2018
One way to do this would be following:
When you operate on each individual row for finding groups using "findgroups" and mean using "splitapply", you can then use the variable "G" to separate the elements belonging to a specific group and subtract the group mean from each element.
For example,
if 'x' is my 100x120 matrix and x_r is a particular row I am operating on, after using these commands:
>> G = findgroups(x_r);
>> mean_mat = splitapply(@mean,x_r,G);
I can subtract the group mean from each element of that group by using the following commands:
>> x_r(G == 1) = x_r(G == 1) - mean_mat(1);
>> x_r(G == 2) = x_r(G == 2) - mean_mat(2);
.
.
.
If the number of groups are small, you can write these commands separately for each group. Otherwise, you can write a loop to do this for each group:
for(i = 1:max(G))
x_r(G == i) = x_r(G == i) - mean_mat(i);
end
  1 Commento
JFz
JFz il 8 Gen 2018
Thank you so much! Let me try it today. Happy New Year!

Accedi per commentare.

Più risposte (2)

Guillaume
Guillaume il 8 Gen 2018
Modificato: Guillaume il 8 Gen 2018
A simpler way, which does not involve loops at all, just simple indexing:
mean_mat = splitapply(@mean, mat, G);
mat_minus_mean = mat - mean_mat(sub2ind(size(mean_mat), repmat(G, 1, size(meat, 2)), repmat(1:size(mat, 2), numel(G), 1)));
The mean_mat(sub2ind(...)) simply creates a matrix the same size as mat whose row r is mean_mat(G(r), :). This is then simply subtracted from mat.
  1 Commento
JFz
JFz il 8 Gen 2018
Thanks! I will try this one too.
If this also works. I will accept both answers. :-).

Accedi per commentare.


JFz
JFz il 8 Gen 2018
I think both answers are correct but I don't know how to choose both.
  2 Commenti
Guillaume
Guillaume il 8 Gen 2018
You cannot accept two answers (but you can vote for as many as you want).
JFz
JFz il 8 Gen 2018
OK. I accepted one and voted for the other. Hehe.

Accedi per commentare.

Tag

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by