Caught in loop

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Dejan Cvijanovic
Dejan Cvijanovic il 7 Mag 2012
My code is as follows:
alpha = 0.5;
beta = 0.1;
a_0 = 1;
dr = 0.1;
dt = input('Value of dt:');
h = 0.001;
c_inf = 0;
c_a = 1;
c_s = 2;
mesh_points = 3;
rho = dt/(dr)^2;
R= 30;
N_i = R/dr;
t_diss = 5.8;
N_t = t_diss/dt;
if rho >= 0.5;
disp('Invalid dt value');
return;
end
for i=1:N_i;
r(i)=(i-1)*dr;
if r(i)< a_0
c(i,1)= c_s;
else
c(i,1)= c_inf;
end
end
a(1) = a_0;
for j = 1:N_t -1;
b_1 = floor (a(j)/dr) + 2;
b_2 = b_1 + 1;
c_ah = (a(j)+h-b_1)*(a(j)+h-b_2)*(c_a)/((a(j)-b_1)*(a(j)-b_2))+h*(a(j)+h-b_2)*c(b_1,j)/((b_1-a(j))*(b_1-b_2)) + h*(a(j)+h-b_1)*c(b_2,j)/((b_2-a(j))*(b_2-b_1));
dc_dr = ((c_ah)-c_a)/h;
a(j+1) = a(j) +dt*beta*dc_dr;
for i=2:N_i - 1;
if r(i) > a(j+1);
d = rho - (rho/(i-1)) - (a(j)^2)*(alpha-1)*(a(j+1)-a(j))/(2*(i-1)^2*(dr)^3);
e = 1-2*rho;
f = rho + (rho/(i-1)) + (a(j)^2)*(alpha-1)*(a(j+1)-a(j))/(2*(i-1)^2*(dr)^3);
c(i, j+1) = d*c(i-1,j) + e*c(i,j) + f*c(i+1, j);
elseif r(i) == a(j+1);
c(i,j+1) = c_a;
else c(i,j+1) = c_s;
end
disp(c(i,j));
end
c(1, j+1) = c(2, j+1);
end
It basically calculates concentration near a dissolving sphere but when it gets to disp(c(i,j)) I get caught in loop of displaying numbers that change periodically. Any ideas?

Risposta accettata

Jan
Jan il 7 Mag 2012
And some cleanup:
...
% Vectorization of the "for i=1:N_i;" loop:
r = (0:N_i) * dr;
c = zeros(N_i, N_t - 1); % Pre-allocate!
c(:, 1) = c_inf;
c(r < a_0, 1) = c_s;
...
dr3 = dr ^ 3;
...
% Reduce repeated calculations inside the "for j = 1:N_t -1" loop:
ajp1 = a(j) +dt*beta*dc_dr;
a(j+1) = ajp1;
tmp1 = (a(j)^2) * (alpha-1) * (ajp1-a(j)) / (2 * dr3);
for i = 2:N_i - 1
if r(i) > ajp1
tmp2 = rho / (i-1) + tmp1 / ((i-1)^2);
d = rho - tmp2;
e = 1 - 2 * rho;
f = rho + tmp2;
c(i, j+1) = d*c(i-1,j) + e*c(i,j) + f*c(i+1, j);
elseif r(i) == ajp1
c(i, j+1) = c_a;
else
c(i, j+1) = c_s;
end
% disp(c(i,j));
end
  5 Commenti
Dejan Cvijanovic
Dejan Cvijanovic il 7 Mag 2012
Got an error: Attempted to access a(1); index out of bounds because numel(a)=0.
Error in CleanDiss (line 36)
ajp1 = a(j) +dt*beta*dc_dr;
Ideas?
Dejan Cvijanovic
Dejan Cvijanovic il 7 Mag 2012
I fixed the error and get these numbers (which make sense):
0.4011
0.3037
0.3882
0.2886
0.3634
0.2649
0.3293
0.2350
0.2886
0.2014
0.2447
0.1667
0.2006
0.1333
0.1589
0.1028
0.1217
0.0766
0.0900
0.0550
0.0643
0.0381
0.0443
0.0254
0.0294
0.0164
0.0189
0.0101
They generally decrease, which is correct but some of them increase, which shouldn't be true?

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Più risposte (1)

Richard Brown
Richard Brown il 7 Mag 2012
Your code works fine. If you remove the disp statement (which is causing it to slow down heaps), you'll find that it runs completely in around 10 seconds or so.
  2 Commenti
Richard Brown
Richard Brown il 7 Mag 2012
Oh, and a hint: Select all the code, then Text->Smart Indent
Image Analyst
Image Analyst il 7 Mag 2012
Cool. Nice trick that I didn't know about.

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