How do you assign into a function space a variable that exists in the caller script?
4 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Patrick Anderson
il 17 Gen 2018
Modificato: Patrick Anderson
il 17 Gen 2018
I have a an anonymous function that uses specific inputs. When I call the function from the caller script, I want to also pass a parameter vector into the function space. However, I can't seem to do this correctly.
I am trying this repeatedly using the "assigning" function, with various permutations of 'base' and 'caller," and can't seem to make it work.
4 Commenti
Steven Lord
il 17 Gen 2018
If you try Stephen's and Walter's advice and it still doesn't work, I recommend showing a small segment of code to illustrate concretely what you're trying to do. Your original problem description was very general, so the advice we could give also could only be general. The more detailed and specific the description of the problem we have, the more focused our suggestions can be.
Risposta accettata
Walter Roberson
il 17 Gen 2018
Demonstration code:
function at
junk = 123;
freedo = 222;
foo = @(junk) fprintf('%d, %d\n', alter1()+junk, alter2()+junk)*0+freedo;
foo(junk)
function r = alter1
assignin('caller', 'junk', 987);
assignin('caller', 'freedo', 111);
r = 0;
function r = alter2
assignin('caller', 'junk', 456);
assignin('caller', 'freedo', 888);
r = 0;
Più risposte (0)
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!