How to replace random integers with the alphabet (1=A, 2=B, and so on)

Hi, Thank you for helping me

I am trying to replace a square matrix of random integers with the alphabet

For instace: A = [1 2; 3 5] should give you A = [A B; C E]

My code is:

 clear all; clc;
n = input('Choose your square matrix dimension: ')
N = round((27)*rand(n))
A = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
for kk = 1:length(N)*2
    N(kk) = A(kk);
end
N

I do not know how to replace the numbers with the alphabet.

Could you help, please?

Thank you very much

Have a nice day.

Answer 1

[Guillaume]

An easiest way to generate random integers is to use randi. As for your replacement it's achieved with simple indexing:

n = input('Choose your square matrix dimension: ');
N = randi(26, n);
A = 'A' : 'Z';

%replacement, note that this requires that all N are strictly positive integer:
NewN = A(N)

[Jaime Vera]

Didn't notice that. Thank you!

Answer 2

[Walter Roberson]

output = repmat(' ', size(N));

and then

output(kk) = A(N(kk));

However, notice that your N includes values that are 0: if the rand() produces a value less than 1/54 then multiplying by 27 would give less than 1/2 and round() of that would be 0.

[Jaime Vera]

You are right. Thank you very much.