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one-by-one matrix assignment

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Antonio
Antonio il 6 Feb 2018
Commentato: Antonio il 6 Feb 2018
I need to find the minimum values in each column of matrix "A", and then replace those min values with the values in last row of matrix "B" (which has same number of columns). Like I have these:
>> A = randi(10,10,5)
A =
3 5 9 5 8
7 6 4 10 2
8 4 1 7 4
4 7 2 8 2
7 5 8 7 5
3 7 10 10 1
5 7 8 5 7
8 3 8 2 3
6 10 2 1 10
3 7 6 7 2
>> B = randi(100,3,5)
B =
10 34 66 18 62
99 95 49 54 81
52 1 52 9 95
>> [M,I] = min(A)
M =
3 3 1 1 1
I =
1 8 3 9 6
And I want to replace the values of "M" with "B(end,:), so that:
A(1,1) = B(end,1);
A(8,2) = B(end,2);
A(3,3) = B(end,3);
A(9,4) = B(end,4);
A(6,5) = B(end,5);
I try "A(I) = B(end,:)" and "A(I(1,:)) = B(end,:)" but they do not work! Any ideas how I could do that? My real matrices are huge (1200x100000) so no way to do it by hand!
  4 Commenti
Jos (10584)
Jos (10584) il 6 Feb 2018
ok. then Andrei's answer suffices.
Antonio
Antonio il 6 Feb 2018
@Jos (10584) great, thanks!

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Risposta accettata

Andrei Bobrov
Andrei Bobrov il 6 Feb 2018
Modificato: Andrei Bobrov il 6 Feb 2018
[~,idx] = min(A);
s = size(A);
A(sub2ind(s,idx,1:s(2))) = B(end,:);

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