Sort all columns in a cell array with labels
3 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Hello everyone
I have the following cell array with text and numeric data:
>> M
M =
5×4 cell array
'' 'Ana' 'Delta' 'Oscar'
'B' [0.9058] [0.9058] [0.9058]
'C' [0.1270] [0.1270] [0.1270]
'D' [0.9134] [ 4] [ 2]
'E' [0.6324] [0.6324] [0.6324]
I would like to sort the data in columns 2, 3 and 4 in descending order (largest to smallest) but also with labels (column 1) and also with labels Ana, Delta and Oscar. I am aware that sortrows can be used for sorting data using a particular column, but I am not sure of the indexing for sortrows or an efficient way of sorting data in columns 2-4 in my cell array M and at the same time having labels next to them.
Thank you for your help.
Suha.
2 Commenti
Stephen23
il 13 Feb 2018
Modificato: Stephen23
il 13 Feb 2018
@Suha: you should really consider putting your data into a table, which natively store data with headers. Then you could apply lots of other functions to the data without having to worry about the first row and column being special cases, e.g. sorting the rows without requiring any indexing at all. It also stores the columns as arrays of an appropriate class, which makes working with the data much easier (putting lots of scalar numeric data into cells of a cell array just makes working with numeric data much more complex than it needs to be).
Risposta accettata
Stephen23
il 13 Feb 2018
Modificato: Stephen23
il 13 Feb 2018
If you do not want to use a table then you would be better off keeping your numeric and cell-of-character data separately, e.g.:
hdr = {'Ana','Delta','Oscar'}
typ = {'B','C','D','E'};
mat = [0.9058,0.9058,0.9058;...
0.1270,0.1270,0.1270;...
0.9134, 4, 2;...
0.6324,0.6324,0.6324];
Then you can trivially sort by rows as you choose:
>> [mat,idx] = sortrows(mat)
mat =
0.12700 0.12700 0.12700
0.63240 0.63240 0.63240
0.90580 0.90580 0.90580
0.91340 4.00000 2.00000
idx =
1
2
3
4
>> typ = typ(idx);
>> typ{:}
ans = B
ans = C
ans = D
ans = E
5 Commenti
Stephen23
il 13 Feb 2018
@Suha: each column might have a different order: is that what you want?
>> [mat,idx] = sort(mat,1)
mat =
0.12700 0.12700 0.12700
0.63240 0.63240 0.63240
0.90580 0.90580 0.90580
0.91340 4.00000 2.00000
idx =
2 2 2
4 4 4
1 1 1
3 3 3
>> out = typ(idx)
'C' 'C' 'C'
'E' 'E' 'E'
'B' 'B' 'B'
'D' 'D' 'D'
Più risposte (1)
Birdman
il 13 Feb 2018
Modificato: Birdman
il 13 Feb 2018
Something like this?
[~,idx]=sort(cell2mat(M(2:end,2:end)),1,'descend');
M(sort(idx)+1,:)=M(idx+1,:)
or
[~,idx]=sortrows(M(2:end,2:end),'descend');
M(sort(idx)+1,:)=M(idx+1,:)
7 Commenti
Birdman
il 13 Feb 2018
It worked perfectly in my case, where each column was sorted independently. Make sure you enter the code correctly, otherwise it should work. I can not attach a screenshot of it at the moment.
Vedere anche
Categorie
Scopri di più su Shifting and Sorting Matrices in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!