integration of a function of two variables in which the limits of integral on one are functions of the other

11 views (last 30 days)
I want to integrate the function f(x,theta)={1-exp[-alpha/sin(theta)]} over x and theta. x has definite limits, but the limits of the integral over theta, are functions of x. So, I don't think I can use intergral2. Any suggestions?

Accepted Answer

Steven Lord
Steven Lord on 1 Mar 2018
"q = integral2(fun,xmin,xmax,ymin,ymax) approximates the integral of the function z = fun(x,y) over the planar region xmin ≤ x ≤ xmax and ymin(x) ≤ y ≤ ymax(x)."
The limits on y can be functions of x. The "Evaluate Double Integral in Polar Coordinates" example on that page includes an example where the upper limit on r is a function of theta.
  3 Comments
Steven Lord
Steven Lord on 1 Mar 2018
You can't perform arithmetic on function handles. You can perform arithmetic on the values you receive from evaluating function handles.
fh = @sin;
x = fh(pi/4).^2 % works
y = fh.^2 % does not work
Evaluate your theta2 and theta1 functions for the values of theta that integral2 passed into your integrand function.

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by