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Anyone who can help a Matlab program that perform the following matrix problem

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I have n by m matrix.I want to find the maximum values for each columns starting from the first column to the last column. However, there is a restriction that only two maximum values are allowed in each rows.
  1 Commento
David Fletcher
David Fletcher il 2 Mar 2018
I'm not really sure I fully understand your intended aim. An example may be useful to clarify the true nature of the problem.

Risposte (1)

John BG
John BG il 2 Mar 2018
Hi Keyre
1.
Let A be your matrix, for instance
m=5;n=8;A=randi([-10 10],n,m)
A
=
7 10 -2 4 -5
9 10 9 5 -10
-8 -7 6 5 -8
9 10 10 -2 7
3 10 3 3 4
-8 0 -10 -7 -4
-5 6 7 4 9
1 -8 9 -10 -10
2.
Combining command sort and flip the columns are arranged top to bottom, max of each column on each top.
B=flip(sort(A))
=
9 10 10 5 9
9 10 9 5 7
7 10 9 4 4
3 10 7 4 -4
1 6 6 3 -5
-5 0 3 -2 -8
-8 -7 -2 -7 -10
-8 -8 -10 -10 -10
3.
Now let's say you want the 3 max elements of each column.
Simply indexing the following way:
B([1:3],:)
=
9 10 10 5 9
9 10 9 5 7
7 10 9 4 4
You get the 3 largest elements of each column
Keyre
If you find this answer useful would you please be so kind to consider marking my answer as Accepted Answer?
To any other reader, if you find this answer useful please consider clicking on the thumbs-up vote link
thanks in advance
John BG
  3 Commenti
John BG
John BG il 7 Mar 2018
Hi Keyre
I chose 3, to show that one can choose any amount of top values (=< amount lines, indeed).
Do you mean this?
trim_top=2;
B([1:trim_top],:)
=
9 10 10 5 9
9 10 9 5 7
Jan
Jan il 8 Mar 2018
@Keyre: If this solves your needs, a hint for a good programming practice: The square brackets waste time here:
B([1:trim_top], :)
This is slightly faster:
B(1:trim_top, :)
[] is the Matlab operator for concatenation, but 1:trim_top is a vector already and there is noting to concatenate. There are further benefits, see Answers: Why not use square brackets.

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