How can I do a 80-20 split on datasets to obtain training and test datasets?

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I tried [training, test] = partition (faceDatabase, [0.8, 0.2]); but it gives me error. Can anyone help? Are there ways to do this manually? I can't find a function for this!

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KSSV
KSSV il 15 Mar 2018
Let P and T be your input and target sets.
PD = 0.80 ; % percentage 80%
Ptrain = P(1:round(PD*length(T)),:) ; Ttrain = T(1:round(PD*length(T))) ;
Ptest = P(round(PD*length(T)):end,:) ;Ttest = T(round(PD*length(T)):end) ;
  2 Commenti
Chidiebere Ike
Chidiebere Ike il 15 Mar 2018
Modificato: Chidiebere Ike il 15 Mar 2018
I tried the code, it says "undefined function or variable T"... I will appreciate if you describe the letter P, T and length ... How do I resolve this. ?

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Più risposte (2)

Akira Agata
Akira Agata il 15 Mar 2018
Modificato: Akira Agata il 15 Mar 2018
If you want to randomly select 80% of your data as training dataset, please try following:
PD = 0.80 ; % percentage 80%
% Let P be your N-by-M input dataset
% Solution-1 (need Statistics & ML Toolbox)
cv = cvpartition(size(P,1),'HoldOut',PD);
Ptrain = P(cv.training,:);
Ptest = P(cv.test,:);
Another possible solution:
% Solution-2 (using basic MATLAB function)
N = size(P,1);
idx = randperm(N);
Ptrain = P(idx(1:round(N*PD)),:);
Ptest = P(idx(round(N*PD)+1:end),:);
  1 Commento
Chidiebere Ike
Chidiebere Ike il 15 Mar 2018
Solution 1 gives an error message.. Error in cvpartition CV.Impl = internal.stats.cvpartitionInMemoryImpl(varargin{:});

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Munshida P
Munshida P il 14 Gen 2020
This will help you.
[training,test] = partition(faceDatabase,[0.8 0.2]);

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