I'm getting an error when I try to use parpool (MATLAB 2018a)
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Helen Marshall
il 4 Apr 2018
Commentato: Srishty Aggarwal
il 10 Set 2022
I'm trying to process some MRI data but the parpool function isn't working. I know there were some bugs in earlier versions of Matlab with macOS Sierra but this shouldn't be happening in the 2018a version?
Error using parpool (line 113) 'size' is not the name of a profile. Valid names are: 'local' 'MATLAB Parallel Cloud'
2 Commenti
Agapi Dav
il 30 Lug 2018
Hi! I have exactly the same problem with matlab R2018a.
Error using parpool (line 113) 'size' is not the name of a profile. Valid names are: 'local' 'MATLAB Parallel Cloud'
I use this command:
if true
% if(~parpool('size'))
parpool
end
end
Can someone help me? Thanks in advance!
Risposta accettata
Agapi Dav
il 31 Lug 2018
I think the problem is that the matlabpool was replaced by parpool. Therefore, matlabpool('size') is not valid anymore and parpool('size') does not do the job.
I found this quick fix here: https://github.com/RobotLocomotion/drake/issues/1009
try
if (matlabpool('size')==0) matlabpool; end
catch
if isempty(gcp('nocreate')) parpool; end
end
For me it worked. Cheers!
P.S. Thanks Ben, new here!
1 Commento
Srishty Aggarwal
il 10 Set 2022
when I use the command, I got the following error
Error using parpool (line 146)
Parallel pool failed to start with the following error. For more detailed information, validate the profile 'local'
in the Cluster Profile Manager.
Caused by:
Error using parallel.internal.pool.AbstractInteractiveClient>iThrowWithCause (line 305)
Failed to initialize the interactive session.
Error using parallel.internal.pool.AbstractInteractiveClient>iThrowIfBadParallelJobStatus (line 426)
The interactive communicating job failed with no message.
How to resolve it?
Più risposte (1)
Ben
il 30 Lug 2018
parpool('size')
as the error says, and you actually want to use
parpool(2) %or whatever number of workers you want
Unless you want to make a non-local parpool. What are you trying to do?
3 Commenti
Agapi Dav
il 31 Lug 2018
So, I had changed something, I forgot. I think the problem was that the matlabpool was replaced by parpool. Therefore, matlabpool('size') is not valid anymore and parpool('size') (as I was trying) does not do the job.
try
if (matlabpool('size')==0) matlabpool; end
catch
if isempty(gcp('nocreate')) parpool; end
end
For me it worked. Cheers!
Ben
il 31 Lug 2018
Yeah, I see that matlabpool was removed in 2015a. If you don't need to support releases before 2015a, you don't need to use a try … catch and can just use parpool by itself (well, the if statement).
Also, you should write your solution in a new answer and accept it so that others with the same problem can see it :)
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