How to write a range of numbers in MATLAB?

Hi, I am trying to generate a speed range in MATLAB. Let V is the speed, then how to write the coding to find the speed range of:

0<V<=12
12<V<=20
20<V<=30
30<V<=40
40<V<=50
50<V<=60
60<V<=70
70<V<=80
80<V<=90
90<V<=100
100<V<=110
V>110

[KALYAN ACHARJYA]

Is this complete question?

[Walter Roberson]

Please do not close Questions that have been Answered.

Answer 1

[Walter Roberson]

https://www.mathworks.com/help/comm/ug/quantization.html

or you can use the second output of histc() or the third output of histcounts()

Answer 2

[njj1]

ranges = [0,12,20:10:110]; %end points of requested speeds
for i = 1:numel(ranges)-1
   v{i} = V((V>ranges(i) & (V<=ranges(i+1))); %speeds between endpoints
   numV{i} = numel(v{i}); %number of speed entries between endpoints
end
v{end+1} = V(V>110);

Answer 3

[Walter Roberson]

theta = (0:60).';

and remember to use cosd() and sind()

Notice the .' there: it is transposing the 0:60 from a row vector into a column vector. When you combine this with row vectors, then the result would be to implicitly expand to two dimensions. For example,

v = 1:100;
theta = (0:60).';
dist = (v - v.^2/100) .* sind(theta);
surf(v, theta, dist, 'edgecolor', 'none')

size(v), size(theta), size(dist)

ans = 1×2

1 100

ans = 1×2

61 1

ans = 1×2

61 100

[rahim njie]

thanks but this didnt work for what im trying to do. i would like to calculate something at every angle between 0-60 degrees. this is my code so far if it helps:

theta= (1:60).'; % precession angle 
w_s = 10;  % angular velocity of spin
a_s = 6;   % angualar acceleration of spin
w_n = 3;   % angular velocity of nutation 
a_n = 2;   % augalar acceleration of nutation 
w_p = 5;   % angular velocity of precession
a_p = 4;   % angular acceleration of precession 
%% Geometry values
rA = [0 7.4103 7.1651];
%% vectors 
vw_s = [0 w_s*sind(theta) w_s*cosd(theta)]; % spin vector
vw_p = [0 0 w_p];                           % precession vector
vw_n = [-w_n 0 0];                          % nutation vector 
%% Angualar velocity 
wi = [-w_n 0 0]; % i component of W
wj = [0 w_s*sind(theta) 0]; % j component W
wk = [ 0 0 (w_p + w_s*cosd(theta))]; % k component of W
W = wi + wj + wk; % Angular Velocity; 

[Walter Roberson]

theta= (1:60).'; % precession angle 
w_s = 10;  % angular velocity of spin
a_s = 6;   % angualar acceleration of spin
w_n = 3;   % angular velocity of nutation 
a_n = 2;   % augalar acceleration of nutation 
w_p = 5;   % angular velocity of precession
a_p = 4;   % angular acceleration of precession 
%% Geometry values
rA = [0 7.4103 7.1651];
%% vectors
Z = zeros(size(theta));
vw_s = [Z, w_s*sind(theta), w_s*cosd(theta)]; % spin vector
vw_p = [0 0 w_p];                           % precession vector
vw_n = [-w_n 0 0];                          % nutation vector 
%% Angualar velocity 
wi = [-w_n 0 0]; % i component of W
wj = [Z w_s*sind(theta) Z]; % j component W
wk = [ Z Z (w_p + w_s*cosd(theta))]; % k component of W
W = wi + wj + wk; % Angular Velocity; 

size(W)

ans = 1×2

60 3

Answer 4

[KSSV]

V = 1:100 ;

idx = V>=10 & V<=20 ;  % Get indices of velocities lying between 10 to 20 
V(idx)

[rahim njie]

does 'v = 1:100' mean a range of numbers between 1-100?

[KSSV]

Yes...you can test it yourself.

v = 1:100

v = 1×100

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

[rahim njie]

thank.

Also i have written code that solves 3D kinematics problem. the code calculates angular velocity at set precsion angle of 60. what function do i use that will allow me to use the same code but calculate the velocity and angle from 1-60 degrees.

i have vectors in some of the calucations so using 'theta= 1:60' Caused erros

thanks