Array manipulation with loop

Hello, I have a question about array manipulation:

Having an array A=[1;2;3;4;5;6] What is a simple way to update the array A so that when it loops, array A becomes: A=[2;3;4;5;6;7] for N times!

The element 7 is calculated from the first 6 elements and the values in the column are to be shifted upwards and the new value is to be replaced with the last value of previous array, for N number of times;

All help is very much appreciated, Thank you in advance!

Answer 1

[Sean de Wolski]

A+N

[Behnaz]

Thanks for the quick response Sean, it worked like a charm.

I was also wondering how I could store all the values of A in another array so it is not limited to 6 (the example);

I'm trying to predict the next value of A for a set of data and compare to my original values and find the error!

Time=[0.015;0.03;0.045;0.06;0.075;0.09;0.105];

A=[17;18.5;20.35;22.4;22.68;23.55;24.1];

for i=1:200

T_i=Time + 0.015;

xfit = linspace(0,0.2,50);

coeffs5 = polyfit(Time, A, 5);

new_A=polyval(coeffs5,T_i);

end

Thanks alot!