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Replacing a value with nan

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Elaheh
Elaheh il 18 Apr 2018
Risposto: Dennis il 18 Apr 2018
Hello all. I want to replace a value that I have in accuracyC with nan if its counterpart value is nan in RTc. RTc and accuracyC are two matrices. I have written this loop but it does not work. I appreciate your help.
h=0;
for i=1:size(accuracyC,1)
for j=1:size(accuracyC,2)
if RTc(i,j)==nan
accuracyC(i,j)=NaN;
h=h+1;
end
end
end

Risposta accettata

Star Strider
Star Strider il 18 Apr 2018

Try this:

RTc = [1 2 3 NaN; 4 5 6 7; NaN 8 9 10]                      % Create Matrix
AccuracyC = randi(9, size(RTc))                             % Create Matrix
AccuracyC(isnan(RTc)) = NaN                                 % Desired Result
RTc =
       1     2     3   NaN
       4     5     6     7
     NaN     8     9    10
AccuracyC =
       7     1     6     6
       8     3     9     3
       1     8     2     1
AccuracyC =
       7     1     6   NaN
       8     3     9     3
     NaN     8     2     1

Più risposte (1)

Dennis
Dennis il 18 Apr 2018

I read about this lately, NaN never equals NaN (some IEEE stuff).

But you can use isnan instead.

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