Time between two dates

Lets say I have a time T1 = '2018-03-14 16:30:54' and another T2 = '2018-03-14 16:40:54' How can I find the total duration of the interval, as well as a "midpoint" in between said interval? My goal is to add an NaN entry every time there is a time gap greater than 10 minutes.

For example; '2018-03-14 16:30:54' '2018-03-14 16:40:54' %NaN entry would be added here '2018-03-14 17:20:15' '2018-03-14 17:30:15'

The purpose of adding this entry would be to remove discontinuity in graphs.

Answer 1

[the cyclist]

T1 = datetime('2018-03-14 16:30:54');
T2 = datetime('2018-03-14 16:40:54');

dT = T2 - T1;

T_mid = T1 + dT/2;

[Miguel Herrera]

Thank you. Follow up question, what can I do to make the following code work if dT > 00:12:00 disp('TRUE') else disp('FALSE') end

I keep getting TRUE even though the answer should be false. Does this have to do with the fact that dT is a duration and should also be compared to another duration using that if statement?

[the cyclist]

There might be a better way, but ...

dT > duration('12:00','InputFormat','mm:ss')

[Peter Perkins]

dT > hours(12)

The cyclists code will work in R2018a or later, but in any case using hours seems much more readable to me.

Answer 2

[Peter Perkins]

>> d = datetime(2018,3,14,16,[30 40],54)
d = 
  1×2 datetime array
   14-Mar-2018 16:30:54   14-Mar-2018 16:40:54
>> mean(d)
ans = 
  datetime
   14-Mar-2018 16:35:54
>> diff(d)
ans = 
  duration
   00:10:00

Answer 3

[Steven Brossi]

How about

T1 = datetime('2018-03-14 16:30:54')

T1 = datetime
   14-Mar-2018 16:30:54

T2 = datetime('2018-03-14 16:40:54')

T2 = datetime
   14-Mar-2018 16:40:54

T_mid = mean([T1, T2])				    

T_mid = datetime
   14-Mar-2018 16:35:54